LoginData.password = document.querySelector('#password'). ername = document.querySelector('#username').value Example: By default the jsondecode () function returns an object.
You just have to use jsondecode () function to convert JSON objects to the appropriate PHP data type. Decoding JSON data in PHP: It is very easy to decode JSON data in PHP. These functions works only with UTF-8 encoded string. LoginBtn.addEventListener('click', displayForm, false) These functions are jsonencode () and jsondecode (). LoginBtn.removeEventListener('click', loginForm, false) then((response) => handleLoginErrors(response))ĭocument.querySelector('#registerMessage').style.display = "none" Hello, I’m working on a project on a local machine/localhost (xampp) and I can’t seem to get the values passed over to the next script with jsondecode( filegetcontents( ‘php://input. * Throw error response if something is wrong:Ĭonst handleLoginErrors = (response) => // Destroy the Login Credentials LoginWelcome = document.querySelector('.welcome') LoginInfo = document.querySelector('#loginInfo'), SubmitBtn = document.querySelector('#submit'), I agree with droopsnoot, you need to JSON-encoded the string.ĭocument.querySelector('.logout').style.display = "none" Ĭonst startBtn = document.querySelector('#startBtn') Ĭonst loginBtn = document.querySelector('#loginMessage') Ĭonst loginForm = document.querySelector('#loginForm')
PHP 7.2: Added JSONINVALIDUTF8IGNORE, and JSONINVALIDUTF8SUBSTITUTE options. PHP Changelog: PHP 7.3: Added JSONTHROWNONERROR option. If the JSON object cannot be decoded it returns NULL. $data2 = file_get_contents('php://input') Return Value: Returns the value encoded in JSON in appropriate PHP type. I’m working on a project on a local machine/localhost (xampp) and I can’t seem to get the values passed over to the next script with json_decode( file_get_contents( ‘php://input’ ))